\(\int \frac {x^5}{\arccos (a x)^2} \, dx\) [52]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [A] (verification not implemented)
   Mupad [F(-1)]

Optimal result

Integrand size = 10, antiderivative size = 70 \[ \int \frac {x^5}{\arccos (a x)^2} \, dx=\frac {x^5 \sqrt {1-a^2 x^2}}{a \arccos (a x)}-\frac {5 \operatorname {CosIntegral}(2 \arccos (a x))}{16 a^6}-\frac {\operatorname {CosIntegral}(4 \arccos (a x))}{2 a^6}-\frac {3 \operatorname {CosIntegral}(6 \arccos (a x))}{16 a^6} \]

[Out]

-5/16*Ci(2*arccos(a*x))/a^6-1/2*Ci(4*arccos(a*x))/a^6-3/16*Ci(6*arccos(a*x))/a^6+x^5*(-a^2*x^2+1)^(1/2)/a/arcc
os(a*x)

Rubi [A] (verified)

Time = 0.05 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {4728, 3383} \[ \int \frac {x^5}{\arccos (a x)^2} \, dx=-\frac {5 \operatorname {CosIntegral}(2 \arccos (a x))}{16 a^6}-\frac {\operatorname {CosIntegral}(4 \arccos (a x))}{2 a^6}-\frac {3 \operatorname {CosIntegral}(6 \arccos (a x))}{16 a^6}+\frac {x^5 \sqrt {1-a^2 x^2}}{a \arccos (a x)} \]

[In]

Int[x^5/ArcCos[a*x]^2,x]

[Out]

(x^5*Sqrt[1 - a^2*x^2])/(a*ArcCos[a*x]) - (5*CosIntegral[2*ArcCos[a*x]])/(16*a^6) - CosIntegral[4*ArcCos[a*x]]
/(2*a^6) - (3*CosIntegral[6*ArcCos[a*x]])/(16*a^6)

Rule 3383

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosIntegral[e - Pi/2 + f*x]/d, x] /; FreeQ
[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]

Rule 4728

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(-x^m)*Sqrt[1 - c^2*x^2]*((a + b*Arc
Cos[c*x])^(n + 1)/(b*c*(n + 1))), x] - Dist[1/(b^2*c^(m + 1)*(n + 1)), Subst[Int[ExpandTrigReduce[x^(n + 1), C
os[-a/b + x/b]^(m - 1)*(m - (m + 1)*Cos[-a/b + x/b]^2), x], x], x, a + b*ArcCos[c*x]], x] /; FreeQ[{a, b, c},
x] && IGtQ[m, 0] && GeQ[n, -2] && LtQ[n, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {x^5 \sqrt {1-a^2 x^2}}{a \arccos (a x)}+\frac {\text {Subst}\left (\int \left (-\frac {5 \cos (2 x)}{16 x}-\frac {\cos (4 x)}{2 x}-\frac {3 \cos (6 x)}{16 x}\right ) \, dx,x,\arccos (a x)\right )}{a^6} \\ & = \frac {x^5 \sqrt {1-a^2 x^2}}{a \arccos (a x)}-\frac {3 \text {Subst}\left (\int \frac {\cos (6 x)}{x} \, dx,x,\arccos (a x)\right )}{16 a^6}-\frac {5 \text {Subst}\left (\int \frac {\cos (2 x)}{x} \, dx,x,\arccos (a x)\right )}{16 a^6}-\frac {\text {Subst}\left (\int \frac {\cos (4 x)}{x} \, dx,x,\arccos (a x)\right )}{2 a^6} \\ & = \frac {x^5 \sqrt {1-a^2 x^2}}{a \arccos (a x)}-\frac {5 \operatorname {CosIntegral}(2 \arccos (a x))}{16 a^6}-\frac {\operatorname {CosIntegral}(4 \arccos (a x))}{2 a^6}-\frac {3 \operatorname {CosIntegral}(6 \arccos (a x))}{16 a^6} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.14 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.90 \[ \int \frac {x^5}{\arccos (a x)^2} \, dx=-\frac {-\frac {16 a^5 x^5 \sqrt {1-a^2 x^2}}{\arccos (a x)}+5 \operatorname {CosIntegral}(2 \arccos (a x))+8 \operatorname {CosIntegral}(4 \arccos (a x))+3 \operatorname {CosIntegral}(6 \arccos (a x))}{16 a^6} \]

[In]

Integrate[x^5/ArcCos[a*x]^2,x]

[Out]

-1/16*((-16*a^5*x^5*Sqrt[1 - a^2*x^2])/ArcCos[a*x] + 5*CosIntegral[2*ArcCos[a*x]] + 8*CosIntegral[4*ArcCos[a*x
]] + 3*CosIntegral[6*ArcCos[a*x]])/a^6

Maple [A] (verified)

Time = 0.80 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.11

method result size
derivativedivides \(\frac {\frac {5 \sin \left (2 \arccos \left (a x \right )\right )}{32 \arccos \left (a x \right )}-\frac {5 \,\operatorname {Ci}\left (2 \arccos \left (a x \right )\right )}{16}+\frac {\sin \left (4 \arccos \left (a x \right )\right )}{8 \arccos \left (a x \right )}-\frac {\operatorname {Ci}\left (4 \arccos \left (a x \right )\right )}{2}+\frac {\sin \left (6 \arccos \left (a x \right )\right )}{32 \arccos \left (a x \right )}-\frac {3 \,\operatorname {Ci}\left (6 \arccos \left (a x \right )\right )}{16}}{a^{6}}\) \(78\)
default \(\frac {\frac {5 \sin \left (2 \arccos \left (a x \right )\right )}{32 \arccos \left (a x \right )}-\frac {5 \,\operatorname {Ci}\left (2 \arccos \left (a x \right )\right )}{16}+\frac {\sin \left (4 \arccos \left (a x \right )\right )}{8 \arccos \left (a x \right )}-\frac {\operatorname {Ci}\left (4 \arccos \left (a x \right )\right )}{2}+\frac {\sin \left (6 \arccos \left (a x \right )\right )}{32 \arccos \left (a x \right )}-\frac {3 \,\operatorname {Ci}\left (6 \arccos \left (a x \right )\right )}{16}}{a^{6}}\) \(78\)

[In]

int(x^5/arccos(a*x)^2,x,method=_RETURNVERBOSE)

[Out]

1/a^6*(5/32/arccos(a*x)*sin(2*arccos(a*x))-5/16*Ci(2*arccos(a*x))+1/8/arccos(a*x)*sin(4*arccos(a*x))-1/2*Ci(4*
arccos(a*x))+1/32/arccos(a*x)*sin(6*arccos(a*x))-3/16*Ci(6*arccos(a*x)))

Fricas [F]

\[ \int \frac {x^5}{\arccos (a x)^2} \, dx=\int { \frac {x^{5}}{\arccos \left (a x\right )^{2}} \,d x } \]

[In]

integrate(x^5/arccos(a*x)^2,x, algorithm="fricas")

[Out]

integral(x^5/arccos(a*x)^2, x)

Sympy [F]

\[ \int \frac {x^5}{\arccos (a x)^2} \, dx=\int \frac {x^{5}}{\operatorname {acos}^{2}{\left (a x \right )}}\, dx \]

[In]

integrate(x**5/acos(a*x)**2,x)

[Out]

Integral(x**5/acos(a*x)**2, x)

Maxima [F]

\[ \int \frac {x^5}{\arccos (a x)^2} \, dx=\int { \frac {x^{5}}{\arccos \left (a x\right )^{2}} \,d x } \]

[In]

integrate(x^5/arccos(a*x)^2,x, algorithm="maxima")

[Out]

(sqrt(a*x + 1)*sqrt(-a*x + 1)*x^5 - a*arctan2(sqrt(a*x + 1)*sqrt(-a*x + 1), a*x)*integrate((6*a^2*x^6 - 5*x^4)
*sqrt(a*x + 1)*sqrt(-a*x + 1)/((a^3*x^2 - a)*arctan2(sqrt(a*x + 1)*sqrt(-a*x + 1), a*x)), x))/(a*arctan2(sqrt(
a*x + 1)*sqrt(-a*x + 1), a*x))

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.89 \[ \int \frac {x^5}{\arccos (a x)^2} \, dx=\frac {\sqrt {-a^{2} x^{2} + 1} x^{5}}{a \arccos \left (a x\right )} - \frac {3 \, \operatorname {Ci}\left (6 \, \arccos \left (a x\right )\right )}{16 \, a^{6}} - \frac {\operatorname {Ci}\left (4 \, \arccos \left (a x\right )\right )}{2 \, a^{6}} - \frac {5 \, \operatorname {Ci}\left (2 \, \arccos \left (a x\right )\right )}{16 \, a^{6}} \]

[In]

integrate(x^5/arccos(a*x)^2,x, algorithm="giac")

[Out]

sqrt(-a^2*x^2 + 1)*x^5/(a*arccos(a*x)) - 3/16*cos_integral(6*arccos(a*x))/a^6 - 1/2*cos_integral(4*arccos(a*x)
)/a^6 - 5/16*cos_integral(2*arccos(a*x))/a^6

Mupad [F(-1)]

Timed out. \[ \int \frac {x^5}{\arccos (a x)^2} \, dx=\int \frac {x^5}{{\mathrm {acos}\left (a\,x\right )}^2} \,d x \]

[In]

int(x^5/acos(a*x)^2,x)

[Out]

int(x^5/acos(a*x)^2, x)